hrothgar, on Oct 26 2007, 02:43 PM, said:
Uhm ... yes, something like that. The density function that minimizes the expected value of p.cond(testday=x), where x is the day on which the test actually takes place, and by p.cond I mean the probabilities assigned the evening before. (This corresponds to your phrasing if "accurately guess" means flipping a weighted coin and have it right. If it means "getting prepared for the test as soon as the probability exceeds 50%", it's a different matter).
Alternatively, one could minimize the expected value of the "information-theoretical" object function log(p.cond(testday=x)) but that leads to meaningless results, not sure why.

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