gwnn, on 2020-January-12, 04:39, said:
It seems like you addressed my point by splitting minimums into good/bad minimums (my points were assuming that 1D-1M; 1NT-2C; 2M showed a non-minimum).
Yes, sorry. But if a hcp range, like the 1
♦ range here, is divided into 'minimum' and 'maximum' without further explanation, I just assume these terms refer to the bottom and top halves of that range, respectively. So when you wrote
gwnn, on 2020-January-08, 06:35, said:
On-topic, I think the simplest thing you can play (that is not too far from optimal) is:
1♣-(transfer)
(complete) = 3-card support
1♦-1M
1NT = 3-card support.
You can even play the same 2♣ relay scheme over both, although with some rearrangements; perhaps you can differentiate diamond length in the relay following 1♦.
For instance:
1♣-(transfer)
(complete)-2♣:
2♦=min unbal (2NT asks)
2♥=min bal (2NT invites)
2♠=max unbal (2NT asks)
1♦-1M
1N-2♣
2♦=min unbal 5+ ♦ (often passed. 2NT asks)
2♥=min unbal 4 ♦ (2NT asks)
2♠=max unbal (2NT asks)
I interpreted 'min' and 'max' as something like "11-15" and "16-21", respectively.
Then I probably got confused by
gwnn, on 2020-January-09, 16:43, said:
after a 1NT rebid showing 3-card support by opener, we can always stop in 2M when opener has no extras
because if
'no extras' = 'min' = "11-15",
then the statement is simply not true given your structure over 1
♦-1M; 1N-2
♣, since the range is so wide that Responder will sometimes need to invite and thereby bypass 2M. It might become a true statement, however, if
'no extras' = my 'bad MIN' = bottom half of "11-15".
---
With this clarification, may I suggest an improvement to your 1N gadget (which I don't hate, btw)?
1
♦-1M; 1N-?:
2
♣ = GF opposite MAX, relay
...2
♦ = bad MIN
......P = allowed
......(...)
...2M = good MIN
...2OM/2N+ = MAX (GF)
(...)
2M = not worth GF opposite MAX
(...)
But in fromageGB's system, where the 1
♦ opening also covers such shapes as 1444, (31)45, (40)45 and (41)35, potentially seriously overloading 1
♦-1
♠; 2
♣(NAT), how about
1
♦-1
♥; ?:
1N = 3 H
other = NAT
1
♦-1
♠; ?:
1N = "4+ C or 1453"
2
♣ = 3 S
other = NAT
1
♦-1M; [1M+2]-?:
2M-2 = GF opposite MAX, relay
...2M-1 = bad MIN
......P(M=
♥) = allowed
......(...)
...2M = good MIN
...[2M+1]+ = MAX (GF)
(...)
2M = not worth GF opposite MAX
(...)
?