Posted 2013-January-16, 03:21
Don, I think you can improve information exchange by combining the first 2 options in the follow-ups. That is
1♥ - 2NT; 3♣ - 3♦
==
3♥ = spade shortage
3♠ = diamond shortage, min
... - 3NT = asks for spade control
... - 4♣ = asks for second club honour
... - 4♦ = asks if diamond loser
3NT = diamond shortage, max, no spade control
... - 4♣ = asks for second club honour
... - 4♦ = asks if diamond loser
4♣ = diamond shortage, max, spade control, no second club honour
... - 4♦ = asks if diamond loser
4♦ = diamond shortage, max, spade control, second club honour, diamond loser
4♥ = diamond shortage, max, spade control, second club honour, no diamond loser
Note that the same scheme also helps with the problem set forth by Cyberyeti.
1♥ - 2NT; 3♦ - 3♥
==
3♠ = min
3NT = max, no spade control
4♣ = max, spade control, no club control
4♦ = max, spade control, club control, diamond loser
4♥ = max, spade control, club control, no diamond loser
Unfortunately not perfectly though, since no loser might be a singleton ace or a void. As usual, that is probably more an advertisement for not splintering with a singleton ace than for changing methods to distinguish it when you do.
FWiiW, I think this is a tough hand without some methods, even with for that matter. It is difficult for North to know if half of their hand is working. South might have KJx/KQxxxx/x/QJx for 3♦ and a 4♣ cue might be based on Jxx/KQxxxxx/x/AQ.
(-: Zel :-)